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翻訳と辞書　辞書検索 [ 開発暫定版 ] スポンサード リンク Lack-of-fit sum of squares ： ウィキペディア英語版 Lack-of-fit sum of squares In statistics, a sum of squares due to lack of fit, or more tersely a lack-of-fit sum of squares, is one of the components of a partition of the sum of squares in an analysis of variance, used in the numerator in an F-test of the null hypothesis that says that a proposed model fits well. == Sketch of the idea == In order for the lack-of-fit sum of squares to differ from the sum of squares of residuals, there must be more than one value of the response variable for at least one of the values of the set of predictor variables. For example, consider fitting a line : $y\; =\; \backslash alpha\; x\; +\; \backslash beta\; \backslash ,$ by the method of least squares. One takes as estimates of ''α'' and ''β'' the values that minimize the sum of squares of residuals, i.e., the sum of squares of the differences between the observed ''y''-value and the fitted ''y''-value. To have a lack-of-fit sum of squares that differs from the residual sum of squares, one must observe more than one ''y''-value for each of one or more of the ''x''-values. One then partitions the "sum of squares due to error", i.e., the sum of squares of residuals, into two components: : sum of squares due to error = (sum of squares due to "pure" error) + (sum of squares due to lack of fit). The sum of squares due to "pure" error is the sum of squares of the differences between each observed ''y''-value and the average of all ''y''-values corresponding to the same ''x''-value. The sum of squares due to lack of fit is the ''weighted'' sum of squares of differences between each average of ''y''-values corresponding to the same ''x''-value and the corresponding fitted ''y''-value, the weight in each case being simply the number of observed ''y''-values for that ''x''-value. Because it is a property of least squares regression that the vector whose components are "pure errors" and the vector of lack-of-fit components are orthogonal to each other, the following equality holds: :$$ \begin &\sum (\text - \text)^2 && \text \\ &\qquad = \sum (\text - \text)^2 && \text \\ &\qquad\qquad + \sum \text\times (\text - \text)^2 && \text \end Hence the residual sum of squares has been completely decomposed into two components. 抄文引用元・出典: フリー百科事典『 ウィキペディア（Wikipedia）』 ■ウィキペディアで「Lack-of-fit sum of squares」の詳細全文を読む スポンサード リンク 翻訳と辞書 : 翻訳のためのインターネットリソース Copyright(C) kotoba.ne.jp 1997-2016. All Rights Reserved.